C hacker needed for easy quesiton

[IronManX]

How do I check to make sure a number is an integer?<br />For a condition?<br /><br />clock is ticking on my homework :/

[Hornication.com]

Truncate it a then check for a remainder. Sorry, I'm not a C programmer, but I can do it in Perl which should be very similar.<br /><br />$x = 5.3;<br />$y = int($x);<br />if ($y == $x){<br />execute something<br />}<br /><br />The if block will only be executed if $x is a whole number. Alternatively, you could route to an error message if $x is not whole.<br /><br />$x = 5.3;<br />$y = int($x);<br />if ($y != $x){<br />error code<br />}

[Hornication.com]

Sorry, I meant to say truncate it and then compare to the original to see if they're equal. It's not really checking for a remainder.

[AgentCash]

Hey Horni, Why not do it the correct way?<br /><br />$x = 5.5;<br />print "Variable is an integer!\n" if ($x =~ /^[+-]?\d+$/);<br /><br /> <img border="0" alt="[Finger]" title="" src="graemlins/finger.gif" />

[IronManX]

Na I don't have that integer function in c

[AgentCash]

I would tell you IronMan, but I stopped doing other people's homework when they stopped being able to beat me up <img border="0" title="" alt="[Big Grin]" src="biggrin.gif" />

[IronManX]

okay here is what I've come up with<br /><br />(number % 2 == 0)<br /><br /> <img border="0" title="" alt="[Big Grin]" src="biggrin.gif" />

[IronManX]

At least I can get even numbers <img border="0" title="" alt="[Smile]" src="smile.gif" />

[Hornication.com]

</font><blockquote><font size="1" face="Verdana, Arial">quote:</font><hr /><font size="2" face="Verdana, Arial">Originally posted by AgentCash:<br /><strong>Hey Horni, Why not do it the correct way?<br /><br />$x = 5.5;<br />print "Variable is an integer!\n" if ($x =~ /^[+-]?\d+$/);<br /></strong></font><hr /></blockquote><font size="2" face="Verdana, Arial">Yup, that works, too. There's always more than one way to do it. We could probably think of a few dozen more, as well. But since yours is the "correct way" I guess I'm missing what was incorrect about mine. Works fine on my computer.<br /><br />Oh well.

[AgentCash]

Hmm... you mustn't be a true perl hacker.... you know it's the correct way if it's the shortest, most obfuscated code around <img border="0" title="" alt="[Big Grin]" src="biggrin.gif" />

[reyes]

Sorry but Im not sure to understand your question.. There is an huge difference in variable declarations of c and perl..<br /><br />You can't assign a float to a variable declared as int, and an int to a variable declared as float..<br /><br />If you're looking to get an int from a float, you can cast it to an int, you will lost the fractionnal part..<br />==================<br />int x<br />float y=3.1416;<br /><br />x=(int)y;<br />==================<br />x is now 3..<br /><br />Best Regards